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-- 专家坐堂 (http://foxtable.net/bbs/list.asp?boardid=2)
---- [求助]添加菜单 (http://foxtable.net/bbs/dispbbs.asp?boardid=2&id=120818)
-- 发布时间：2018/6/24 17:45:00
-- [求助]添加菜单
老师，
希望用for each 逐行一次添加菜单（因为还有其他代码原因，不想通过递归添加，因为还有其他代码是for each 按照行生成的）
可以看到，到第三级顺序 就不对了，如何能按照for each 逐行 添加上菜单
[此贴子已经被作者于2018/6/24 17:49:30编辑过]
-- 发布时间：2018/6/24 20:25:00
--
Dim Striptab As WinForm.Strip= e.Form.Strips.Add("ca", StripTypeEnum.MainMenu)
\'添加菜单按钮分割线
Dim DT As DataTable=DataTables("表A")
Dim levels As new List(of object)
levels.add(striptab)
For Each dr1 As DataRow In DataTables("表A").Select("", "menuid")
Select Case dr1("mentype")
Case "StripItemTypeEnum.MenuItem"
For i As Integer = levels.count-1 To 0 Step -1
If dr1("menuid").contains(levels(i).name) Then
Dim obj = levels(i).Items.Add(dr1("menuid"),dr1("poutcaption"),dr1("imgsmlt"),val(dr1("mentype")))
levels.add(obj)
Exit For
End If
Next
End Select
Next
-- 发布时间：2018/6/24 21:24:00
--
老师 ，
好久不见了，代码好用，但是放到我的例子中，就不行了，没办法，烦您再给看看。
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此主题相关图片如下：qq图片20180624212312.png
-- 发布时间：2018/6/24 21:28:00
--
我写的只能生成到二级，按照您给的例子，怎么写进去呢，标注颜色是第一次向您求助的部分？
Dim e =args(0)
Dim pnl As WinForm.Panel=args(1)
Dim Striptab As WinForm.Strip
Dim StriptabName As String=pnl.name.Replace("pnl","menu")
If forms("serevmain").Strips.Contains(StriptabName) Then
forms("serevmain").Strips.Remove(StriptabName)
End If
Dim dt As DataTable=Functions.Execute("tablloading","usperation")
Select Case pnl.name.split("_")(0)
Case "toolpnl"
Striptab= FormS("serevmain").Strips.Add(StriptabName, StripTypeEnum.MainMenu)
Striptab.Items.Add(StriptabName.replace("toolmenu","gb_"),"","Tools_exit.png",StripItemTypeEnum.Button)
Striptab.Items(StriptabName.replace("toolmenu","gb_")).DisplayText = False
Striptab.Items(StriptabName.replace("toolmenu","gb_")).DockToRight = True \'靠右停放
Case "findpnl"
Striptab= FormS("serevmain").Strips.Add(StriptabName, StripTypeEnum.ToolBar)
Case "stripnl"
Striptab= FormS("serevmain").Strips.Add(StriptabName, StripTypeEnum.StatusBar)
End Select
pnl.basecontrol.controls.add(Striptab.basecontrol)
\'添加菜单按钮分割线
Dim drsbj As List (of DataRow)
drsbj=dt.Select(pnl.name.split("_")(0) & "=true" & " and id=\'"& pnl.name.split("_")(2) &"\'","itmoder")
If drsbj.count>0 Then
Dim i1 As Integer=0
For Each dr1 As DataRow In drsbj
Select Case dr1("mentype")
Case "StripItemTypeEnum.Separator"
Striptab.Items.Add(pnl.name.Replace("pnl","Separator" & i1 ),"","",StripItemTypeEnum.Separator)
Case "StripItemTypeEnum.MenuItem"
Dim drslsb As DataRow=lsb("readrules").find("tbltname=\'zamenuset\' And tblcolid=\'menuid\'")
If drslsb IsNot Nothing Then
Dim count As Integer= 0
Dim count2 As Integer= 0
For i As Integer = 0 To drslsb("colong").length - 1
count += val(drslsb("colong").chars(i))
count2=val(drslsb("colong").chars(i))
If count <= dr1("menuid").length Then
Dim str As String = dr1("menuid").Substring(0,count)
\'Dim drf As DataRow=dt.find(pnl.name.split("_")(0) & "=true And id=\'" & pnl.name.split("_")(2) & "\' And mentype=\'"& dr1("mentype") &"\' And menuid like\'"& str &"%\' And menuid <> \'"& str &"\'")
\'Dim drf As DataRow=dt.find(pnl.name.split("_")(0) & "=true And id=\'" & pnl.name.split("_")(2) & "\' And mentype=\'"& dr1("mentype") &"\' And menuid =\'"& str &"\'")
\'\'If drf IsNot Nothing Then
Dim drf2 As DataRow=dt.find(pnl.name.split("_")(0) & "=true And id=\'" & pnl.name.split("_")(2) & "\' And mentype=\'"& dr1("mentype") &"\' And menuid =\'"& str.SubString(0,str.length-count2) &"\'")
If drf2 IsNot Nothing Then
If Striptab.Items.Contains(str.SubString(0,str.length-count2))=False Then
Dim dr2 As DataRow=dt.find("menuid=\'"& str.SubString(0,str.length-count2) &"\'")
If dr2 IsNot Nothing Then
Striptab.Items.Add(str.SubString(0,str.length-count2),dr2("poutcaption"),dr2("imgsmlt"),val(dr2("mentype")))\'还要改下
End If
Else
Dim Stripitm As WinForm.StripItem= Striptab.Items(str.SubString(0,str.length-count2))
If Stripitm.Items.Contains(str)=False Then
Dim dr2 As DataRow=dt.find("menuid=\'"& str &"\'")
If dr2 IsNot Nothing Then
Stripitm.Items.Add(str,dr2("poutcaption"),dr2("imgsmlt"),val(dr2("mentype")))
End If
End If
End If
Else
If Striptab.Items.Contains(str)=False Then
Dim dr2 As DataRow=dt.find("menuid=\'"& str &"\'")
If dr2 IsNot Nothing Then
Striptab.Items.Add(str,dr2("poutcaption"),dr2("imgsmlt"),val(dr2("mentype")))
End If
End If
End If
End If
Next
End If
Case "StripItemTypeEnum.Label","StripItemTypeEnum.SplitButton","StripItemTypeEnum.Button"
Striptab.Items.Add(dr1("menuid"),dr1("poutcaption"),dr1("imgsmlt"),val(dr1("mentype")))
Striptab.Items(dr1("menuid")).DisplayText = True
End Select
i1=i1+1
Next
End If
[此贴子已经被作者于2018/6/24 21:40:14编辑过]
-- 发布时间：2018/6/24 23:40:00
--
你发的例子和你的描述不符，你的例子要做到什么效果？
-- 发布时间：2018/6/24 23:46:00
--
老师，
3楼 顺序添加图片上的菜单控件 ，根据表A的前两列生成的，因为 有BTN 有分割线还有菜单，那么希望按照表列的顺序，FOR EACH 逐行生成。
[此贴子已经被作者于2018/6/24 23:49:06编辑过]
-- 发布时间：2018/6/25 9:19:00
--
Dim Striptab As WinForm.Strip= e.Form.Strips.Add("", StripTypeEnum.MainMenu)
\'添加菜单按钮分割线
Dim DT As DataTable=DataTables("表A")
Dim levels As new List(of object)
levels.add(striptab)
For Each dr1 As DataRow In DataTables("表A").Select("", "menuid")
Dim T = Nothing
Select Case dr1("mentype")
Case "StripItemTypeEnum.MenuItem"
t = StripItemTypeEnum.MenuItem
Case "StripItemTypeEnum.Button"
\'t = StripItemTypeEnum.Button
t = StripItemTypeEnum.MenuItem
Case "StripItemTypeEnum.Separator"
t = StripItemTypeEnum.Separator
End Select
If t IsNot Nothing Then
For i As Integer = levels.count-1 To 0 Step -1
If dr1("menuid").contains(levels(i).name) Then
Dim obj = levels(i).Items.Add(dr1("menuid"),dr1("poutcaption"),dr1("imgsmlt"),t)
obj.text = dr1("poutcaption")
levels.add(obj)
Exit For
End If
Next
End If
Next