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| -- 作者：薛翁 -- 发布时间：2020/6/30 14:39:00 -- [求助] Dim a1,a2,a3,a4,a5,a6,a7,a8,a9,a10,a11,a12,a13,a14,a15,a16,a17,a18,a19,a20,a21,a22 As Double Dim a23,a24,a25,a26,a27,a28,a29,a30,a31,a32,a34,a35,a36,a37,a38 As Double Dim a39,a40,a41,a42,a43,a44,a45,a46,a47,a48,a49,a50,a51,a52,a53,a54,a55 As Double Dim a56,a57,a58,a59,a60,a61,a62,a63 As Double For Each r1 As Row In Tables("工作表").Rows If r1.checked Then For js As Integer = 1 To 63 a & js = 0.00 Next ...... next 在每次循环中，这63个变量都应先清0，编译提示 a & js = 0.00出错。 运行过程中也要给变量动态赋值。 请老师告诉我该如何处理，非常感谢! |
| -- 作者：有点蓝 -- 发布时间：2020/6/30 14:51:00 -- 考虑使用字典 Dim zd As New Dictionary(Of String, double) zd.add("a1",0) zd.add("a2",0) …… For Each r1 As Row In Tables("工作表").Rows If r1.checked Then For js As Integer = 1 To 63 zd("a" & js) = 0 Next ...... next [此贴子已经被作者于2020/6/30 14:52:12编辑过]
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