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---- 打印一张如图所示的签名表，怎么设计？ (http://foxtable.net/bbs/dispbbs.asp?boardid=2&id=177443)
-- 发布时间：2022/5/22 21:25:00
-- 打印一张如图所示的签名表，怎么设计？
想设计打印如图所示的签名表：
此主题相关图片如下：微信截图_20220522211710.png
代码如何写？
要求：序号顺序填充1-69，姓名有几人填充几人，小于23人时，在第二列，小于46人时，填充完第二列再填充第五列，依次类推，大于69人时，到下一页，签字列空白。
自己写了点代码，不对，哪位老师帮忙改一下，谢谢！
-- 发布时间：2022/5/22 21:53:00
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参考：http://www.foxtable.com/webhelp/topics/2241.htm，其它细节的东西自己处理
Dim doc As New PrintDoc
Dim tb As Table = Tables("表A")
Dim prs As Integer = 69
Dim caps() As String = {"序号", "姓名", "签字", "序号", "姓名", "签字", "序号", "姓名", "签字"}
For p As Integer = 0 To math.Ceiling(tb.Rows.Count / prs) - 1
Dim rx As New prt.RenderText
rx.Text = "公司活动签名表"
rx.Style.Font = New Font("宋体", 16, FontStyle.Bold)
rx.Style.TextAlignHorz = prt.AlignHorzEnum.Center
rx.Style.Spacing.Bottom = 3
Doc.body.Children.Add(rx)
Dim rt As New prt.RenderTable
rt.Cols.Count = 9
rt.Cols(0).Width = 10 \'设置各列宽度
rt.Cols(1).Width = 15
rt.Cols(2).Width = 20
rt.Cols(3).Width = 10
rt.Cols(4).Width = 15
rt.Cols(5).Width = 20
rt.Cols(6).Width = 10
rt.Cols(7).Width = 15
rt.Cols(8).Width = 20
rt.Style.Gridlines.All = New prt.Linedef(Color.Gray)
rt.CellStyle.Spacing.All = 0.5
rt.Cells(0, 0).SpanCols = 2
rt.Cells(0, 0).Text = "企业名称"
rt.Cells(0, 2).SpanCols = 3
rt.Cells(0, 2).Text = "xxx" \'rw("企业名称")
rt.Cells(0, 5).SpanCols = 2
rt.Cells(0, 5).Text = "活动日期"
rt.Cells(0, 7).SpanCols = 2
rt.Cells(0, 7).Text = "2022-05-22" \'rw("培训时间")
rt.Cells(1, 0).SpanCols = 2
rt.Cells(1, 0).Text = "培训主题"
rt.Cells(1, 2).SpanCols = 7
rt.Cells(1, 2).Text = "xxx" \'rw("培训主题")
Dim idx As Integer = 2
For c As Integer = 0 To caps.Length - 1
rt.Cells(idx, c).Text = caps(c)
Next
idx = 3
Dim cl As Integer = 0
Dim i As Integer = 1
For r As Integer = p * prs To math.min(tb.Rows.Count - 1, ( p + 1) * prs - 1)
If idx >= 26 Then
idx = 3
cl = cl + 3
End If
rt.Cells(idx, cl).Text = i
rt.Cells(idx, cl + 1).Text = tb.rows(r)("姓名")
idx += 1
i += 1
Next
If p < math.Ceiling(tb.Rows.Count / prs) - 1 Then
rt.BreakAfter = prt.BreakEnum.Page
End If
doc.Body.Children.Add(rt)
Next
doc.Preview()
-- 发布时间：2022/5/23 18:55:00
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谢谢蓝老师！