师傅你好，对狐表我是初学，在边看帮助边操作过程中遇到一些问题，只有向师傅请教，才能进一步得到提高，同时也希望师傅不要怕烦，在此，本人表示衷心的感谢！

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点击浏览该文件:生产管理.rar

这是我写的代码，不能自动显示

Select Case e.DataCol.Name
    Case "品种","型钢_规格","排档_规格", "托圈_规格", "角钢腰圈_规格", "元钢腰圈_规格", "拉丝圆_规格", "中板_规格", "护缆圈_规格", "钢管_规格", "加固角钢_规格", "螺母_规格", "弹垫_规格"
        Dim dr2 As DataRow
        Dim fls As String
        fls = "盘具名称 = \'" & dr1("品种") & "\' And 钢材规格 = \'" & dr1("型钢_规格") & "\' And 钢材规格 = \'" & dr1("排档_规格") & "\'And 钢材规格 = \'" & dr1("托圈_规格") & "\' And 钢材规格 = \'" & dr1("角钢腰圈_规格") & "\' And 钢材规格 = \'" & dr1("元钢腰圈_规格") & "\' And 钢材规格 = \'" & dr1("拉丝圆_规格") & "\' And 钢材规格 = \'" & dr1("中板_规格") & "\' And 钢材规格 = \'" & dr1("护缆圈_规格") & "\' And 钢材规格 = \'" & dr1("钢管_规格") & "\' And 钢材规格 = \'" & dr1("加固角钢_规格") & "\' And 钢材规格 = \'" & dr1("螺母_规格") & "\' And 钢材规格 = \'" & dr1("弹垫_规格") & "\'"                                               
        dr2 = DataTables("参数").Find(fls)
        If dr2 IsNot Nothing Then
            dr1("型钢_单价") = dr2("钢材单价")
            dr1("排档_单价") = dr2("钢材单价")
            dr1("托圈_单价") = dr2("钢材单价")
            dr1("角钢腰圈_单价") = dr2("钢材单价")
            dr1("元钢腰圈_单价") = dr2("钢材单价")
            dr1("拉丝圆_单价") = dr2("钢材单价")
            dr1("中板_单价") = dr2("钢材单价")
            dr1("护缆圈_单价") = dr2("钢材单价")
            dr1("钢管_单价") = dr2("钢材单价")
            dr1("加固角钢_单价") = dr2("钢材单价")
            dr1("螺母_单价") = dr2("钢材单价")
            dr1("弹垫_单价") = dr2("钢材单价")
        End If
End Select

是盘具成本表

看看你的条件，全部是钢材规格:

fls = "盘具名称 = \'" & dr1("品种") & "\' And 钢材规格 = \'" & dr1("型钢_规格") & "\' And 钢材规格 = \'" & dr1("排档_规格") & "\'And 钢材规格 = \'" & dr1("托圈_规格") & "\' And 钢材规格 = \'" & dr1("角钢腰圈_规格") & "\' And 钢材规格 = \'" & dr1("元钢腰圈_规格") & "\' And 钢材规格 = \'" & dr1("拉丝圆_规格") & "\' And 钢材规格 = \'" & dr1("中板_规格") & "\' And 钢材规格 = \'" & dr1("护缆圈_规格") & "\' And 钢材规格 = \'" & dr1("钢管_规格") & "\' And 钢材规格 = \'" & dr1("加固角钢_规格") & "\' And 钢材规格 = \'" & dr1("螺母_规格") & "\' And 钢材规格 = \'" & dr1("弹垫_规格") & "\'"                                               

每一行的钢材规格列只是一个值，怎么可能同时等于多个值？ 这等于你要求一个人身高必须同时等于150、160、170、180cm，会有这样的人吗，因为人的身高只有一个。

你应该拆分成多个：

Select Case e.DataCol.Name
    Case "品种","型钢_规格"
        Dim dr2 As DataRow
        Dim fls As String
        fls = "盘具名称 = \'" & dr1("品种") & "\' And 钢材规格 = \'" & dr1("型钢_规格") & "\'"
        dr2 = DataTables("参数").Find(fls)
        If dr2 IsNot Nothing Then
            dr1("型钢_单价") = dr2("钢材单价")
        End If
End Select
Select Case e.DataCol.Name
    Case "品种",""排档_规格"
        Dim dr2 As DataRow
        Dim fls As String
        fls = "盘具名称 = \'" & dr1("品种") & "\' And "钢管_规格 = \'" & dr1(""钢管_规格") & "\'"
        dr2 = DataTables("参数").Find(fls)
        If dr2 IsNot Nothing Then
            dr1("钢管_单价") = dr2("钢材单价")
        End If
End Select
....

师傅你好：

按上面写法也不显示

列名错了，要一一对应：

Select Case e.DataCol.Name
    Case "品种",""排档_规格"
        Dim dr2 As DataRow
        Dim fls As String
        fls = "盘具名称 = \'" & dr1("品种") & "\' And "钢管_规格 = \'" & dr1(""钢管_规格") & "\'"
        dr2 = DataTables("参数").Find(fls)
        If dr2 IsNot Nothing Then
            dr1("排档_单价") = dr2("钢材单价")
        End If
End Select

Select Case e.DataCol.Name
    Case "品种",""排档_规格"
        Dim dr2 As DataRow
        Dim fls As String
        fls = "盘具名称 = \'" & dr1("品种") & "\' And "钢管_规格 = \'" & dr1(""钢管_规格") & "\'"
        dr2 = DataTables("参数").Find(fls)
        If dr2 IsNot Nothing Then
            dr1("排档_单价") = dr2("钢材单价")
        End If
End Select

这组代码确定时出现错误提示

编译错误：应为语句结束

错误代码：case "品种"，" "排档_规格"

错误代码：case "品种"，" "排档_规格"   ：  这不是告诉你了嘛，多了个 " 号

就是去了也不行

我还是无法解决，只有师傅能够处理